ผมลอง preg_match แบบนี้แล้ว
Code: Select all
echo "<hr>".$number_urlimg;
preg_match_all("/images\/(.*)./", $number_urlimg, $old_name_img_oley);
Moderators: mindphp, ผู้ดูแลกระดาน
Post by jamepiyawat » 03/12/2019 3:03 pm
Code: Select all
echo "<hr>".$number_urlimg;
preg_match_all("/images\/(.*)./", $number_urlimg, $old_name_img_oley);
Post by mindphp » 03/12/2019 3:04 pm
Post by jamepiyawat » 03/12/2019 3:19 pm
Code: Select all
"/images\/(.*)\./"
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